Mafiascum.net

In post 3048, MathBlade wrote:You’re not able to put yourself as town in a hypothetical.

you're talking about limming someone on the wagon

I'm one of them

wtf

*pokes self*

Yep! I still exist. Sometimes I am seemingly irrational like my avatar but eventually circle around to the point.

(This is a joke)

In post 3050, Dwlee99 wrote:

In post 3048, MathBlade wrote:You’re not able to put yourself as town in a hypothetical.

you're talking about limming someone on the wagon

I'm one of them

wtf

Correct. It’d be 50/50 to you if you’re town.

The alternative is to explain how that wagon is all town.

Why wouldn't I include the possibility of limming me?

HURT: voyc

I'm fake voting here, do what you want math

In post 3054, Dwlee99 wrote:Why wouldn't I include the possibility of limming me?

Because if you’re town you know you’re not scum. So again from your POV it’s 50/50.

And I already stated I am fake voting you so…

It's only not 50/50 if I assume I'm unlimmable, which is clearly not the case

If a group of players has ONE SCUM

You shouldn't lim in there when a group of 7 has 3. This is basic math

In post 3057, Dwlee99 wrote:It's only not 50/50 if I assume I'm unlimmable, which is clearly not the case

Lol nice back track
On wagon is: 0/2 = 0% 1/2 = 50% odds or 2/2 = 100% odds
Vs
Off wagon is 0/4 , 1/4, 2/4, 3/4.

It’s pretty likely scum were on the jester wagon early

You haven’t countered the assumption I fail to see a reason I should look elsewhere.

It’s not about elim ability it’s about probability.

There are 3 people on the wagon my guy

Right

I think max one of them is scum

That means one in three if people agree that only one of them is scum

If we lim off the wagon and my assumption is right, the odds are 2/4 or 3/4.

Which is higher

Your name is mathblade

Even if magically everyone agrees that limming on wagon won't include me, that's still 50/50, aka equal or worse than the odds off

In post 3061, Dwlee99 wrote:There are 3 people on the wagon my guy

Right

I think max one of them is scum

That means one in three if people agree that only one of them is scum

If we lim off the wagon and my assumption is right, the odds are 2/4 or 3/4.

Which is higher

Your name is mathblade

You’re assuming I am wrong to prove I am wrong. That’s not how any of this works lmao.
Of course if I am wrong and it’s all town then off wagon is correct, because any percent is greater than 0.

If you think the wagon on M&M was all town, towncase numberq

I said there is at most one scum on wagon. Are you misunderstanding or misrepping?

Like math: do you think I'm scum with number? If so, then yea limming on wagon would make sense. But even if you think one of number and I is scum, fypov limming off wagon is equal odds to hit scum. I seriously do not understand what is so hard to comprehend about this, and my patience for you completely derailing any actual discussion in favor of doing what this is is thin

And if it wasn't clear: I don't have a town case on number. I have never had one. Look at 3038. Your "we have to vote on wagon" math is awful, I've already explained why your probabilities aren't good and so I'm not subscribing to it and I'm done discussing it. Voyc IS scummy. Do you have a town case there? No, you don't, because I don't think you've even looked at their posts. Maybe number is scum. Maybe number is town. It doesn't really matter, because we have to vote one scum at a time, and my belief about the wagon scum composition and voyc's play makes me think this is the best shot to hit scum

In post 2737, Kerset wrote:

Vote Count 2.12

With 12 votes in play, it takes 7 to eliminate.


RH9 (7): Voyc, mc esther, MegAzumarill, Three, Firebringer, numberQ, Milk & Mocha,
Milk & Mocha (3):Enchant, RH9, Dwlee99,
Alyssa The Lamb (2): Harley Quinn,
Three (1): Alyssa The Lamb,
Voyc (0):
Enchant (0):
Firebringer (0):
numberQ (0):
mc esther (0):
Dwlee99 (0):
Harley Quinn (0):
MegAzumarill (0):

Not Voting

(0):

Deadline:

(expired on 2022-01-08 22:16:26)

Harley Quinn is on V/LA

It's voyc/HQ/mega probably

Vote count unrelated

In post 1424, Kerset wrote:

Vote Count 1.10

With 14 votes in play, it takes 8 to eliminate.


Toogeloo (5):

marcistar

,

Blood Puppets

,

Three

,

Andante

,

Milk & Mocha

,

Milk & Mocha

(3): Toogeloo, numberQ,

Dwlee99

,
Looker (1): Looker,

Dwlee99

(1): Harley Quinn,

RH9

(1): Voyc,
numberQ (0):
Harley Quinn (0):
Three (0):
Andante (0):
marcistar (0):
Blood Puppets (0):
ahhlo (0):
Voyc (0):
MegAzumarill (0):

Not Voting

(2):

RH9

, MegAzumarill,

Deadline:

(expired on 2021-12-26 15:45:40)

Wow what a cool vote count. I hope it doesn't prove a central thesis of MathBlade's wagon argument entirely bunk (or mathblade is scum)

I changed NM but forgot to change toog. That's your slot with five not scum votes on it. What's that about math?

Voyc reveal now

Mathblade, your point of there must be 1 scum on the Jester wagon isn't compelling in part because I think every player alive right now would join that wagon, the ones that did were just the ones that hit the thread first.

The only person you could make an arguement that they didn't want to be on the wagon for whatever is me, which I covered why on that day ( was waiting on people to get to post, but still intended to put the wagon at E-1)

.