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Backgammon(looking for opponent)
Posted: Fri Jul 03, 2020 4:43 pm
by NoPowerOverMe
Code: Select all
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Rules:
*The winner is the person to get all pices to the end of the board.
*Each player rolls 2 dice to begin the game. Higher roll goes first and is X. The higher rolls roll is their first roll.
*Players take turns rolling 2d6 and moving pieces according to the dice. Each die corresponds to exactly one piece moved.
*If a player rolls doubles, they get to move four pieces instead of two.
*If a piece is landed on, it goes back to the start.
*If a game row has two pieces or more on it, it can not be landed on.
*If a player has no eligible moves, they must pass their turn.
*A player must move if they are eligible to, they cannot voluntarily pass their turn.
*If a players pawn has been captured, they must roll on an open row to move, that is one that has 0 or 1 pieces on it. If they cannot eligibly move their peices out due to being blocked they pass their turn.
*When moving pieces into the end box, rolls do not have to be exact. If a piece is 4 away and they roll a 5, for example, they can still move the piece into the end box.
*If you are playing a multi point game, at any time a player may "double". At that time the opponent has the choice to forfeit the game at the current stakes, or accept the double and raise the stakes. At any time a player may double again and the same rules apply. For example, if the cube gets to 4, then the winner gets 4 points. If, for example, it was a 10 point game, then 6 additional points would be needed to win the match.
Posted: Sat Jul 04, 2020 4:00 am
by NoPowerOverMe
Still need an opponent.
Posted: Sat Jul 04, 2020 8:50 am
by Plotinus
I'll play
Original Roll String: 2d6
2 6-Sided Dice: (2, 1) = 3
Posted: Sat Jul 04, 2020 9:22 am
by NoPowerOverMe
10 points?
Original Roll String: 2d6
2 6-Sided Dice: (4, 1) = 5
Posted: Sat Jul 04, 2020 9:24 am
by NoPowerOverMe
Code: Select all
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12-16, 16-17
Posted: Sat Jul 04, 2020 6:24 pm
by Plotinus
Sure. I've usually only played to odd numbers before, but we can do ten.
Original Roll String: 2d6
2 6-Sided Dice: (1, 2) = 3
Posted: Sat Jul 04, 2020 6:27 pm
by Plotinus
Code: Select all
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13/9 24/23
Posted: Sat Jul 04, 2020 9:43 pm
by NoPowerOverMe
Original Roll String: 2d6
2 6-Sided Dice: (3, 3) = 6
Posted: Sat Jul 04, 2020 9:47 pm
by NoPowerOverMe
Code: Select all
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17/23, 19/23
Posted: Sat Jul 04, 2020 9:48 pm
by NoPowerOverMe
We can play 11 if you prefer.
Posted: Sat Jul 04, 2020 10:12 pm
by Plotinus
11 sounds good
Original Roll String: 2d6
2 6-Sided Dice: (6, 1) = 7
Posted: Sat Jul 04, 2020 10:14 pm
by Plotinus
Code: Select all
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25/22, 24/22
Posted: Sat Jul 04, 2020 10:17 pm
by NoPowerOverMe
Original Roll String: 2d6
2 6-Sided Dice: (3, 3) = 6
Posted: Sat Jul 04, 2020 10:19 pm
by NoPowerOverMe
Code: Select all
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17/18, 17/18, 1/2, 1/2
Posted: Sat Jul 04, 2020 10:30 pm
by Plotinus
Original Roll String: 2d6
2 6-Sided Dice: (2, 6) = 8
Posted: Sat Jul 04, 2020 10:32 pm
by Plotinus
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22/20(2), 13/9
Posted: Sat Jul 04, 2020 10:34 pm
by NoPowerOverMe
thinking about doubling, but not yet.
Original Roll String: 2d6
2 6-Sided Dice: (2, 3) = 5
Posted: Sat Jul 04, 2020 10:35 pm
by NoPowerOverMe
Code: Select all
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12-19
Posted: Sat Jul 04, 2020 10:42 pm
by Plotinus
Original Roll String: 2d6
2 6-Sided Dice: (2, 6) = 8
Posted: Sat Jul 04, 2020 10:44 pm
by Plotinus
Code: Select all
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8/5, 6/5
Posted: Sat Jul 04, 2020 10:44 pm
by NoPowerOverMe
Original Roll String: 2d6
2 6-Sided Dice: (3, 2) = 5
Posted: Sat Jul 04, 2020 10:46 pm
by NoPowerOverMe
Code: Select all
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17-18, 19-21
Posted: Sat Jul 04, 2020 10:48 pm
by Plotinus
double
Posted: Sat Jul 04, 2020 10:50 pm
by NoPowerOverMe
accept
Posted: Sat Jul 04, 2020 10:52 pm
by Plotinus
Original Roll String: 2d6
2 6-Sided Dice: (1, 4) = 5