It's not as simple as TGP puts it. Here's what I see:
Let's inspect the info we are given here:
1- There are 3 Scum alive = Not all 4 listed players are Scum = at least one of the 4 is Town
2- There is |at least" one scum in each of the intersecting trios
Possibilities:
- If shelly is Scum both pools contain "at least one scum" regardless of the alignment of the other 3
- If TGP is scum both pools contain "at least one scum" regardless of the alignment of the other 3
- If BOTH shelly & TGP are scum both pools contain "at least one scum" regardless of the alignment of the other 2
- Only if BOTH shelly/TGP are Town are Taylor/Chemist BOTH confirmed to be scum
To me, this means one of many things:
1- shelly is scum, TGP/Taylor/chemist are Town
2- shelly/TGP are scum. Taylor/Chemist are Town
3- shelly/Taylor are Scum, TGP/chemist are Town
4- shelly/chemist are scum, TGP/Taylor are Town
5- shelly/TGP/Taylor are Scum, Chemist is Town
6- shelly/TGP/chemist are scum, Taylor is Town
7- shelly/Taylor/Chemist are Scum, TGP is Town
All 7 possibilities are valid assuming shelly is Scum. HOWEVER, assuming shelly is Town we get:
8- TGP is scum, shelly/Taylor/chemist are Town
9- TGP/Taylor are scum, shelly/chemist are Town
10- TGP/Chemist are Scum, shelly/Taylor are Town
11- TGP/Taylor/chemist are scum, shelly is Town
12- chemist/Taylor are Scum, TGP/shelly are Town
I hope I didn't miss any other combination (everyone feel free to re-investigate the possibilities)
Conclusion: Voting NOW is STUPID. 4 votes on a Townie and Scum can quick!eliminate the subject (as hard as this may be it is still possible albeit improbable)
So, PLEASE
until we can figure this out, or -at least- have an idea of what we are doing. THANK YOU